A surface tilted 45° from horizontal and pointed 10° west of due south is located at 35°N latitude. Calculate the incident angle at 2 h after local noon on June 15.


From Example 2.6 we have 6 = 23.35° and the hour angle = 30°. The solar incidence angle 9 is calculated from Eq. (2.18):

cos(9) = sin(35)sin(23.35)cos(45) - cos(35)sin(23.35)sin(45)cos(10) + cos(35) cos(23.35) cos(30) cos(45) + sin(35) cos(23.35) cos(30) sin(45) cos(10) + cos(23.35) sin(30) sin(45) sin(10) = 0.769


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