The Clausius-Clapeyron equation (4.8.1) is exact and may be applied to the case of the variation of the melting-point of ice with pressure. For this, we invert the Eq. (4.8.1) and obtain dT/des = T(v2 - v3)/Le (T) (4.8.7)
where we write Le (T) for the latent heat of melting of ice (or fusion of water) and v3 for the volume of 1 mol of ice. Since the specific volume of ice is greater than that of water, i.e., v3 > v2, the right-hand side of (4.8.7) is negative. This means that the melting-point of ice is lowered by increase of pressure.
Was this article helpful?